An electromagnetic radiation given byE=E0[sin(2π ν1t)+sin(2π ν2t)] is incident on a photocell whose work function is 2.0 eV. Then the maximum kinetic energy (upto 2 decimal points accuracy) of photoelectrons will be eV[Take h=4.14×10−15 eVs ; ν1=1.3×1015 Hz and ν2=1.1×1015 Hz]

An electromagnetic radiation given byE=E0[sin(2π ν1t)+sin(2π ν2t)]

1.	An electromagnetic radiation given byE=E0[sin(2π ν1t)+sin(2π ν2t)] is incident on a photocell whose work function is 2.0 eV. Then the maximum kinetic energy (upto 2 decimal points accuracy) of photoelectrons will be eV[Take h=4.14×10−15 eVs ; ν1=1.3×1015 Hz and ν2=1.1×1015 Hz]
Answer» An electromagnetic radiation given by $E = E_{0} [sin (2 π ν_{1} t) + sin (2 π ν_{2} t)]$ is incident on a photocell whose work function is $2.0 eV$ . Then the maximum kinetic energy (upto $2$ decimal points accuracy) of photoelectrons will be $eV$ [Take $h = 4.14 \times 10^{- 15} eVs; ν_{1} = 1.3 \times 10^{15} Hz$ and $ν_{2} = 1.1 \times 10^{15} Hz$ ]

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An electromagnetic radiation given byE=E0[sin(2π ν1t)+sin(2π ν2t)] is incident on a photocell whose work function is 2.0 eV. Then the maximum kinetic energy (upto 2 decimal points accuracy) of photoelectrons will be eV[Take h=4.14×10−15 eVs ; ν1=1.3×1015 Hz and ν2=1.1×1015 Hz]

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