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An electrolytic cell contains a solution of AgNO_(3) and Pt electrodes. A current is passed until 1.6 gm of O_(2) has been liberated at anode. The amount of Ag deposited has liberated at cathode would be |
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Answer» 1.6 G Now 1F `-=` 107.8 g of AG. `THEREFORE 0.2F -=21.6` g of Ag. |
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