1.

An electrolytic cell contains a solution of AgNO_(3) and Pt electrodes. A current is passed until 1.6 gm of O_(2) has been liberated at anode. The amount of Ag deposited has liberated at cathode would be

Answer»

1.6 G
0.8 g
21.6 g
10.788 g

Solution :1.6 g of `O_2-=0.2F `of ELECTRICITY
Now 1F `-=` 107.8 g of AG.
`THEREFORE 0.2F -=21.6` g of Ag.


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