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An electrical appliance has a rating 100 W, 120 V. the resistance of element of appliance when in use is:(a) 1.2Ω (b) 144 Ω (c) 120 Ω (d) 100 Ω |
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Answer» 144Ω Solution: Given, power (p) = 100 w Potential difference, v = 120 volt ∴ Resistance, r = (v)2/P = (120)2/100 = 144 Ω |
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