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An electric lamp which runs at 80 volt d.c. and consumes 10 ampere is connected to 100 volt, 50 Hz a.c. mains. Calculate the inductance of the choke required. |
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Answer» Here, `V = 80 V, I = 10 A`, `R = (V)/(I) = (80)/(10) = 8 Omega` `E_(v) = 100 V, v = 50 Hz, I_(v) = I = 10 A, L = ?` If Z is impedance of lamp and choke coil, then `Z = (E_(v))/(I_(v)) = (100)/(10) = 100 Omega` As `R^(2) + X_(L)^(2) = Z^(2)` `:. X_(L)^(2) = Z^(2) - R^(2) = 10^(2) - 8^(2) = 36, X_(L) = 6 Omega` Now `X_(L) = omega L = 2 pi v L` `:. L = (X_(L))/(2 pi v) = (6 xx 7)/(2 xx 22 xx 50) = 1.9 xx 10^(-2) H` |
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