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An electric heater of resistance 8 ohm draws 15A from the service mains for 2 hours.Calculate the rate at which heat is developed in the heater. |
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Answer» Solution :Here, 1= 15 A, `R = 8 Omega, t = 2H` The rate at which heat is developed in theheater means its ELECTRIC power, `P =I^2R` `=(15)^2 xx 8 =225 xx8 1800 W =1800 J/s` |
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