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An electric heater has a resistance of 40Ω and draws a current of 4A. Calculate : 1. its power 2. p.d. at its ends |
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Answer» (i) Power P = I2R, R = 40Ω I = 4A P = 4 x 4 x 40 = 640W (ii) P.d. at its ends V = p/I = 640/4 = 160V |
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