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an electric field of 200 volt per metre exist between the plates of parallel plate capacitor of separation between the plates 5 cm what is the potential difference between the plates then a dielectric slab of dielectric constant 4 and thickness 5 cm is inserted between the plates |
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Answer» Initial voltage=200Vq=C.Vq= dϵ 0 .A V (1)When dielectric is inserted q remains CONSTANT and V decreases by k.q= d ′ +t− KT ϵ 0 A V (2)From EQUATION 1 and 2 we have,d=d ′ +t− kt d−d ′ =1.6mm=2− k2 solving,k=5Explanation:HEY shilka mark me as brainliest |
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