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An electric field is uniform and E=200 hatiNC^(-1) along +xs and E=-200hatiNC^(-1) along -x direction. A right circular cylinder of length 0.20 m and radius 0.05 m has its centre at the origin and its axis along the x-axis so that one face is x=+0.10m and the other =x-0.10m. a. What is the net outward flux through each flat face? b. What is the flux through the side of the cylinder? c. What is the net outward flux throught the cylinder? d. What is the net charge inside the cylinder? |
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Answer» Solution :(a) we cansee from thethat on the leftfaceE and `triangle S`are parallel THEREFORE the outward fluxis (b) for any pointon the side of the CYLINDER E is perpwendicular to `triangle S` and hence E `triangleS=0`thereforethe fluxout of the side ofthe cylinder is zero (c ) net outward flux throughthe cylinder `Phi =1.57 +1.57 +0=3.14 N m^(2) c^(-1)`  (d) the netcharge WITHIN the cylinder can be foundby using gauss.slaw which GIVES `q=epsilon_(0) Phi` `=2.78 xx10^(-11) c` |
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