An electric field is acting vertically upwards. A small body of mass 1 gm and charge –1μC is projected with a velocity 10 m/s at an angle 45∘ with horizontal. Its horizontal range is 2m then the intensity of electric field is: (g = 10 m/s2)

An electric field is acting vertically upwards. A small body of mass 1

1.	An electric field is acting vertically upwards. A small body of mass 1 gm and charge –1μC is projected with a velocity 10 m/s at an angle 45∘ with horizontal. Its horizontal range is 2m then the intensity of electric field is: (g = 10 m/s2)
Answer» An electric field is acting vertically upwards. A small body of mass 1 gm and charge –1 $μ C$ is projected with a velocity 10 m/s at an angle $45^{\circ}$ with horizontal. Its horizontal range is 2m then the intensity of electric field is: (g = 10 $m / s^{2}$ )

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An electric field is acting vertically upwards. A small body of mass 1 gm and charge –1μC is projected with a velocity 10 m/s at an angle 45∘ with horizontal. Its horizontal range is 2m then the intensity of electric field is: (g = 10 m/s2)

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