1.

An electric engine has a velocity of 120 kmh-1. How much distance will it travel in 30s?

Answer»

Now, | velocity l =120 kmh-1

= \(\frac{120\times1000}{2600} ms^{-1}\)

\(= \frac{100}{3}ms^{-1}\)

Now, time = 30 s

Hence, Distance = |velocity| \(\times\) time

\(=\frac{100}{3}\times30\)

= 1000 m

= 1 km

Hence the distance travelled by the electric engine in 30 s is 1 km.


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