1.

An electric discharge is passed through a containing 50cc of O_(2) and 50cc of H_(2). The volume of the gases formed (i) at room temperature, (ii) at 110^(@)C will be:

Answer»

i 25 cc II 50cc
i50cc ii 75cc
i 25cc ii 75cc
i 75cc ii 75cc

Solution :`2H_(2)(g)+O_(2)(g)rarr2H_(2)O`
50cc `H_(2)` will COMBINE with 25 cc `O_(2)` to form 50 cc `H_(2)O`
`therefore O_(2)` left=25cc
At room temperature `H_(2)O` will be in liquid state but at `110^(@)C`, it will be gaseous. Thus, volume of gases at `25^(@)C` and `110^(@)C` will be 25cc and 75cc RESPECTIVELY.


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