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An electric dipole of moment P is released in a uniform electric field E from the position of maximum torque. Angular velocity of the dipole when P becomes parallel to E will be (I= moment of inertia of dipole) A) √2PE/IB) √PE/IC) √4PE/ID) √2I/PE |
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Answer» An electric dipole of moment P is released in a uniform electric field E from the position of maximum torque. Angular velocity of the dipole when P becomes parallel to E will be (I= moment of inertia of dipole) A) √2PE/I B) √PE/I C) √4PE/I D) √2I/PE |
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