An electric dipole of moment →p=(^i−3^j+2^k)×10−29 Cm, is at the origin. The electric field due to this dipole at →r=+^i+3^j+5^k (note that →r⋅→p=0) is parallel to:

An electric dipole of moment →p=(^i−3^j+2^k)×10−29 Cm, is at th

1.	An electric dipole of moment →p=(^i−3^j+2^k)×10−29 Cm, is at the origin. The electric field due to this dipole at →r=+^i+3^j+5^k (note that →r⋅→p=0) is parallel to:
Answer» An electric dipole of moment $\to p = (^i - 3^j + 2^k) \times 10^{- 29} Cm$ , is at the origin. The electric field due to this dipole at $\to r = +^i + 3^j + 5^k$ (note that $\to r \cdot \to p = 0)$ is parallel to:

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An electric dipole of moment →p=(^i−3^j+2^k)×10−29 Cm, is at the origin. The electric field due to this dipole at →r=+^i+3^j+5^k (note that →r⋅→p=0) is parallel to:

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