1.

An electric current when passed through dilute sulphuric acid for 2 hours liberated 0.50 g of hydrogen . What weight of copper will be liberated if the same current is passed for one hour through copper sulphate solution ?

Answer»

7.94 G
15.97 g
31.75 g
63.50 g

Solution :0.5 g of `H_(2)` =1/2 Equivalent of `H_(2)` `-=48,250` COULOMBS
`therefore ` 48,250 Coulbombs `-=15.87 g ` of Cu for 2 hours
`therefore ` 1 hours of same current will produce 7.94g of Cu.


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