an electric bulb of resistance 200 ohm draws a current of 1 ampere . c

1.	an electric bulb of resistance 200 ohm draws a current of 1 ampere . calculate the power of the potentoal diff at its ends and the energy in kwh consumed it for 5hour
Answer» We know that power,P = I^2 RSo P = 11200 = 200 Watts Energy = PtSo, E = 200*5 = 1000 Watt hour = 1 kWh Hope it helps.Mark as best if I am correct.

an electric bulb of resistance 200 ohm draws a current of 1 ampere . calculate the power of the potentoal diff at its ends and the energy in kwh consumed it for 5hour

Answer»

We know that power,P = I^2 *RSo P = 1*1*200 = 200 Watts

Energy = P*tSo, E = 200*5 = 1000 Watt hour = 1 kWh

Hope it helps.Mark as best if I am correct.