1.

An echo is returned in `3 s`. What is the distance of the reflecting surface from the source, given that the speed of sound is `342 m//s`.

Answer» Here, speed of sound, `v = 342 m//s`
time taken by echo to return, `t = 3 s`
If `d` is the distance between the source and the reflecting surface,
distance covered by sound in time `t = d + d = 2 d`
(distance `d` while going to the reflecting surface and distance d while returning back)
As distance = speed (of sound) `xx` time,
`2 s = 342 (m//s) xx 3 (s) = 1026 m`
or `s = 513 m`.


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