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An echo is returned in `3 s`. What is the distance of the reflecting surface from the source, given that the speed of sound is `342 m//s`. |
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Answer» Here, speed of sound, `v = 342 m//s` time taken by echo to return, `t = 3 s` If `d` is the distance between the source and the reflecting surface, distance covered by sound in time `t = d + d = 2 d` (distance `d` while going to the reflecting surface and distance d while returning back) As distance = speed (of sound) `xx` time, `2 s = 342 (m//s) xx 3 (s) = 1026 m` or `s = 513 m`. |
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