1.

An automobile starting from rest Speeds upto 12 m/s with a constant acceleration of 1.2 m/s²,runs at this speed For a time and finally comes to rest with a deceleration of 1.5 m/s².If the total distance travelled is 366m,Find the total time required

Answer» EXPLANATION:u=0m/sv=12m/sa=1.2m/s^2v2=0-a=-1.5m/s^2s=366mt=(v-u)/at=12-0/1.2=10 ss1=ut+1/2(at)^2s1=1/2*1.2*10*1.2*10=50*1.44=72ms2=366-72=294mu2=v=12m/ss=ut+1/2(at)^2294=12*t+1/2*2.25*t^2294=12t+2.25t^2/2t=11.6(APPROX.)TOTAL time=11.6+10=21.6 s


Discussion

No Comment Found

Related InterviewSolutions