An athlete completes one round of a circular track of diameter 49m in 20s. Calculate the distance covered and displacement at the end of 30s.

An athlete completes one round of a circular track of diameter 49m in

1.	An athlete completes one round of a circular track of diameter 49m in 20s. Calculate the distance covered and displacement at the end of 30s.
Answer» Hey man.. Answer.. Given,, TIME taken to complete one round = 20s So,total rounds completed in 30S = 30/20 = 3/2 = 1.5 Given:diameter = 49 therefore radius = 49/2 and pi = 3.14 Now distance travelled in one round = 2pir = 23.1449/2 = 3.1449 = 153.86 thus,total distance travelled in 30s = 1.5153.86 = 230.79m To find the displacement, the shortest distance between initial and final position in diameter = 49M thus,displacement of an ATHLETE completes one round of a circular TRACK = 49m _____________&__________ Help you.

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An athlete completes one round of a circular track of diameter 49m in 20s. Calculate the distance covered and displacement at the end of 30s.

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