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An Athelete covers a circular loop of radius 100 m find distance and displacement1-in an completing 1 loop2- in covering 1/2 of the loop3- in covering 1/4 of the loop |
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Answer» RADIUS of loop = 100m (1)DISTANCE covered in covering 1 loop = 2πr = 2*22/7*100 = 4400/7m = 628.57m displacement = 2r = 2×100 = 200m (2) in covering 1/2 loop distance= 628.57/2 = 314.28 m displacement = 2r = 2(100) = 200m (3) distance covered in covering 1/4 TH loop = 1/4*628.57 = 157.14 m displacement = r = 100m |
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