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an athelet runs along a circular track of radius 50m.find the distance travelled and the displacement of the athlete when he covers 3/4 th of the circle |
| Answer» DISTANCE is 235.5Displacement is 78.5Explanation:THETA=90 degree = 90×π/180 = π/2 radianArc LENGTH = theta × r = π/2 × 50 =78.5 = DISPLACEMENT. Distance = 2πr - Displacement = ( 2×3.14×50) - 78.5 =314 - 78.5 = 235.5Hope! I help you Thanks........... | |