An artillery shell is fired from x=0 so as to land in one piece at x=1000 m. Instead it explodes at the top of its parabolic trajectory into two pieces of equal mass. The first piece lands at x=750 m. The other piece happens to hit the ground at the same instant. It lands at x= (in m)

An artillery shell is fired from x=0 so as to land in one piece at x=1

1.	An artillery shell is fired from x=0 so as to land in one piece at x=1000 m. Instead it explodes at the top of its parabolic trajectory into two pieces of equal mass. The first piece lands at x=750 m. The other piece happens to hit the ground at the same instant. It lands at x= (in m)
Answer» An artillery shell is fired from $x = 0$ so as to land in one piece at $x = 1000 m$ . Instead it explodes at the top of its parabolic trajectory into two pieces of equal mass. The first piece lands at $x = 750 m$ . The other piece happens to hit the ground at the same instant. It lands at $x =$ (in $m$ )

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An artillery shell is fired from x=0 so as to land in one piece at x=1000 m. Instead it explodes at the top of its parabolic trajectory into two pieces of equal mass. The first piece lands at x=750 m. The other piece happens to hit the ground at the same instant. It lands at x= (in m)

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