1.

An artificial satellite circulating the earth is at a height 3400 km from the surface of earth. If the radius of the earth is 6400 km and g = 9.8ms^-2, calculate the orbital velocity of the satellite.

Answer»

SOLUTION :`v_0` = `SQRT(GM)/(R_g+h)` = `sqrt(gR_g^2)/(R_g+h)` = `sqrt(9.8 XX(6400xx10^3))^2/sqrt((6400 + 3400) 10^3` = `6400ms^-1`


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