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An aromatic compound 'X' (C_(8)H_(8)Br_(2)) on treatment with aqueous KOH gives 'y' (C_(8)H_(9)BrO). On heating 'X' with alcoholic KOH, 'Z' (C_(8)H_(7)Br) is formed the compound 'Z' on reacting Br_(2)//C Cl_(4) forms 'A'. The compound 'A' reacts with fused KOH to give 'B'. Identify all the compound that are involved. |
Answer» Solution :The compound 'y' formed by REACTING 'X' with aqueous KOH is an alcohol 'y' which CONTAINS one Br atom. This showthat one of the Br atoms in compound 'X' is a PART of side chain while the other is ATTACHED to the ring preferable at the para position. the series of reactions involved and the corresponding compounds formed are GIVEN: .
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