An army contingent of 616 member is to march behind an army bound of 3

1.	An army contingent of 616 member is to march behind an army bound of 32 member in parade .The two groups are to march in the same number of columns . What is the maximum number of columns in which they lan march?
Answer» Answer: answer is below my questioner. Step-by-step explanation: HCF (616,32) is the maximum number of columns in which they can march. Step 1: First find which integer is larger. 616>32 Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain 616=32×19+8 Repeat the above step until you will get remainder as ZERO. Step 3: Now consider the divisor 32 and the remainder 8, and apply the division lemma to get 32=8×4+0 Since the remainder is zero, we cannot PROCEED further. Step 4: Hence the divisor at the LAST PROCESS is 8 So, the H.C.F. of 616 and 32 is 8. Therefore, 8 is the maximum number of columns in which they can march.

An army contingent of 616 member is to march behind an army bound of 32 member in parade .The two groups are to march in the same number of columns . What is the maximum number of columns in which they lan march?

Answer»

Answer:

answer is below my questioner.

Step-by-step explanation:

HCF (616,32) is the maximum number of columns in which they can march.

Step 1: First find which integer is larger.

616>32

Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain

616=32×19+8

Repeat the above step until you will get remainder as ZERO.

Step 3: Now consider the divisor 32 and the remainder 8, and apply the division lemma to get

32=8×4+0

Since the remainder is zero, we cannot PROCEED further.

Step 4: Hence the divisor at the LAST PROCESS is 8

So, the H.C.F. of 616 and 32 is 8.

Therefore, 8 is the maximum number of columns in which they can march.

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