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An are lamp requires a direct current of 10A at 80V to function. If it is connected to a 220V(rms), 50 Hz AC supply, the series inductor needed for it to work is close to:A. 0.044HB. 0.065HC. 80HD. 0.08H |
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Answer» Correct Answer - B here, `i=(e)/(sqrt(R^(2)+X_(L)^(2)))=(e)/(sqrt(R^(2)+omega^(2)L^(2)))=(e)/(sqrt(R^(2)+4 pi^(2)v^(2)L^(2)))` `10=(220)/(sqrt(64xx4 pi ^(2)(50^(2)L` [`:. R=v//(i) = 80/18]` pm solving we get ltbr. `L=0.065h`. |
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