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An aqueous solution of salt 'R' when treated with dil. HCl, a colourless gas is given out. The gas so evolved when passed through acidified KMnO_(4) decolourisesKMnO_(4) solution. The salt 'R' is |
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Answer» `Na_(2)CO_(3)` Since the gas decolourises acidified `KMnO_(4)` solution so it is `SO_(2)` and thus the anion present is `SO_(3)^(2-)` i.e., the salt .R. is `Na_(2)SO_(3)`. |
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