1.

An aqueous solution of NaCI is marked 10% W/W on the borrle. The density of soution is 1.071 g mL^(-1). Calculate its molarity.

Answer»


Solution :`"Mass of solution"=100g," Mass of NACI"=10 g`
`"Density of soluion "1.071" g ML"^(01)`
`"VOLUME of 100 g of solution"= ("Mass of solution")/("Density of solution")=((100g))/((1.071" g mL"^(-1)))=93.37mL`
`"Molarity of solution (M)"=("Mass of solute/Molar mass of solute")/("Volume of solution in litres")`
`=((10G))/((58.5"g mol"^(-1))xx0.0934L)=1.83" mol L"^(-1) or 1.83 M`


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