1.

An aqueous solution of a non-electrolyte solute boils at 100.52^(@)C. The freezing point of the solutiion will be (K_(f) = 1.86 K kg "mol"^(-1), K_(b) = 0.52 K kg"mol"^(-1))

Answer»

`0^(@)C`
`-1.86^(@)C`
`1.86^(@)C`
none of the above.

Solution :`DELTA T_(B) = K_(b) xx m`
`i=e.,0.52 = 0.52 xx m` or m=1
`Delta T_(f) =K_(f) xx m = 1.86 xx 1 = 1.86^(@)`
`i.e., T_(f) = T_(F)^(@)-Delta T_(f) = 0^(@) C-1.86^(@)C=1.86^(@)C`


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