1.

An aqueous solution of a dibasic acid (mol. Mass = 118) containing 35.5 g of the acid per litre of the solution has density 1.0077g//cm^(3). Express the concentration of the solution in as many ways ways as you can.

Answer»


Solution :`"Molarity "=(35.4)/(118)"mol L"^(-1)="0.3M,Noramality "=(35.4)/(118//2)"G EQ L"^(-1)=0.6N`
`1000CM^(3) " solution "=1000xx1.0077 g = 1007.7 g`
`"Solvent (WATER) "=1007.7 - 35.4=972.3 g = 0.9723 kg`
`"Molality "=("35.4/118 mol")/("0.9723 kg")=0.3085 ~=0.31 , x_(2)=(n_(2))/(n_(1)+n_(2))=(35.4//118)/(972.3//18+35.4//118)=0.0055`
`x_(1)=1-x_(2)=0.9945.`


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