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An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of 0.1 N NaOH required to completely neutralise 10 mL of this solution is :A. 40 mLB. 20 mLC. 10 mLD. 4 mL |
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Answer» Correct Answer - A Normality of oxalic acid solution `= (6.3)/(250)xx(1000)/(63)=0.4N` Volume of NaOH solution required is calculated by applying normality equation `N_(1)V_(1) -= N_(2)V_(2)` `0.1 xx V_(1) -= 0.4 xx 10` `V_(1)=(0.4xx10)/(0.1)=40mL`. |
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