1.

An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of 0.1 N NaOH required to completely neutralise 10 mL of this solution is :A. 40 mLB. 20 mLC. 10 mLD. 4 mL

Answer» Correct Answer - A
Normality of oxalic acid solution
`= (6.3)/(250)xx(1000)/(63)=0.4N`
Volume of NaOH solution required is calculated by applying normality equation
`N_(1)V_(1) -= N_(2)V_(2)`
`0.1 xx V_(1) -= 0.4 xx 10`
`V_(1)=(0.4xx10)/(0.1)=40mL`.


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