1.

An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of 0.1 N NaOH required to completely neutralise 10 mL of this solution is :

Answer»

`40 mL`
`20 mL`
`10 mL`
`4 mL`

Solution :Equivalent mass of OXALIC acid
`=126/2=63`
Normally of exalic acid
`=6.3/63xx1000/250=0.4N`
`underset(("oxalic acid"))(N_(1)V_(1))=underset((NaOH))(N_(2)V_(2))`
`0.4xx10=0.1xxV_(2)`
`V_(2)=(0.4xx10)/(0.1)=40ML`


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