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An aqueous solution freezes at -0.2^(@)C. What is the molality of the soluiton ? Determines also (i) elevation in the boiling point (ii) lowering of vapour pressure at 298 K, given that K_(f)=1.86^(@)"kg mol"^(-1),K_(b)=0.512^(@)" kg mol"^(-1) and vapour pressure of water at 298 K is 23.756 mm.

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Solution :`"For (ii) :"Delta T_(f)=(1000K_(f)w_(2))/(w_(1)M_(2))=(1000K_(f)n_(2))/(n_(1)M_(1))`.
Calculate `(n_(2))/(n_(1))`. Then APPLY `(Deltap)/(p^(@))=(n_(2))/(n_(1))." Calculate "Delta p.`


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