An aqueous solution freezes at -0.186c kf =1.86 kb=0.512.what is the e

1.	An aqueous solution freezes at -0.186c kf =1.86 kb=0.512.what is the elevation on boiling point
Answer» Depression in freezing POINT (ΔTf) = KF x m 0.186 = 1.86 x m m = 0.1 Now as we have got the molality, m= 0.1 ELEVATION in boiling point (ΔTb) = Kb x m → ΔTb = 0.512 x 0.1 → ΔTb = 0.0512 Therefore, the elevation in Boiling point is 0.0512. Hope it HELPS!!

An aqueous solution freezes at -0.186c kf =1.86 kb=0.512.what is the elevation on boiling point

Answer»

Depression in freezing POINT (ΔTf) = KF x m

0.186 = 1.86 x m

m = 0.1

Now as we have got the molality, m= 0.1

ELEVATION in boiling point (ΔTb) = Kb x m

→ ΔTb = 0.512 x 0.1

→ ΔTb = 0.0512

Therefore, the elevation in Boiling point is 0.0512.

Hope it HELPS!!