1.

An aqueous solution freezes at -0.186^(@)C (K_(f)=1.86^(@) ,K_(b)=0.512^(@). What is the elevation in boiling point?

Answer»

0.186
0.512
0.86
0.0512.

SOLUTION :For the same solution
`(DeltaT_(B))/K_(b)=(DeltaT_(b))/K_(F)`
of `DeltaT_(b)=(DeltaT_(f))/(T_(f))xxK_(b)`
`=((0.186^(@)C))/1.86xx0.512.`
=`0.0512^(@)C`


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