1.

An aqueous solution contains 5% by weight of urea and 10% by weight of glucose. What will be its freezing point? (Molal depression constant of water is 1.86^(@)C).

Answer»


Solution :`"Mass of solution = 100 g ,Mass of urea = 5 g"`
`"Mass of GLUCOSE = 10"therefore "Mass of water "=100-(5+10)=85h`
`"Molality of urea in the solution "=(5)/(60)xx(1000)/(85)=0.98m`
`"Molality of glucose in the solution "=(10)/(180)xx(1000)/(85)=0.65m`
Total `DeltaT_(f)=K_(f)(m_(1)+m_(2))=1.86(0.98+0.65)=3.03^(@)C`
`therefore"Freezing point of the solution "=-3.03^(@)C.`


Discussion

No Comment Found

Related InterviewSolutions