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An aqueous solution contains 5% and 10% of urea and glucose respectively (by weight). Find freezing point of the solution . K_(f) for water =1.86 |
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Answer» Solution :We have `DeltaT_(F)=K_(f)xx` molality `=K_(f)xx` no. of moles of solute PER `1000g` of solvent `=1.86xx((5)/(60)+(10)/(180))xx(1000)/(85)=3.03` `{{:("urea"=60),("glucose"=180):}}` Since PURE water freezes at `0^(@)C`, the f.p. of the solution will be `-3.03^(@)C` |
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