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An aqueous solution contains 10g of glucose (mol.wt. =180) per 0.5L . Assuming the solution to be ideal calculate osmatic pressure at 25^(@)C |
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Answer» Solution :Mole of GLUCOSE `=(10)/(180)=(1)/(18)`, `V=0.5L` `R=0.082` lit. ATM / K / mole `T=273+25=298K` We have, `p=(n)/(V) RT` `=(1//18)/(0.5)xx0.082xx298` `=2.715atm` |
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