1.

An aqueous solution containing 6.5 g of NaCl of 90% purity was subjected to electrolysis.After the complete electrolysis, the solution was evaporated to get solid NaoH. The volume of 1 M acetic acid required to neutralise NaOH obtained above is

Answer»

`2000 cm^(3)`
`100 cm^(3)`
`200 cm^(3)`
`1000 cm^(3)`

SOLUTION :WEIGHT of NaCl`=6.5xx90/100=5.85g`
No. of equivalents of NaCl
`=("WT. of " Nacl)/("mol. Mass of" NaCl)=5.85/58.5=0.1`
No. of equivalents of NaOH OBTAINED =0.1
`:.N_(NaOH)xxV_(NaOH)xxN_(CH_(3)COOH)xxV_(CH_(3)COOH)`
`implies0.1xx1000=1xxV_(CH_(3)COOH)`
`impliesV_(CH_(3)COOH)=100cm^(3)`


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