An aqueous solution containing 12.48 g of barium chloride in 1.0 kg of water boils at 373.08321K.Calculate the d.egree of dissociation of barium I chloride. (Given K_(b), of H_(2)O = 0.52 K m^(-1), molar mass of Ba CI_(2) = 208.34 g mol^(-1)]

An aqueous solution containing 12.48 g of barium chloride in 1.0 kg of

1.	An aqueous solution containing 12.48 g of barium chloride in 1.0 kg of water boils at 373.08321K.Calculate the d.egree of dissociation of barium I chloride. (Given K_(b), of H_(2)O = 0.52 K m^(-1), molar mass of Ba CI_(2) = 208.34 g mol^(-1)]
Answer» Solution :`W_(R) = 12.48 ` G of `BaCI_(2)` `W_(A) = 1 `kg Boiling POINT of solution = 373.0832 K Degree of DISSOCIATION of `BaCI_(2)`= ? `K_(b)=0.52 km^(-1)` `M_(B)= 208.34` g/mol . Boiling point of water =373 K `T_(b) = iK_(b)m` `0.0832 = ixx0.52xx(12.48)/(208.34) xx1 kg ` `i= (208.34xx0.0832)/(0.52xx12.48)` `=(17.33)/(6.48)` i = 2.67 `BaCI_(2)= Ba^(2+)+ 2CI^(-) ` 1 mol `""` 0 `""` 0 `1-alpha "" alpha "" 2 alpha` Total 1 + 2 `alpha` `i =1 +2 alpha ` or `alpha = (i-1)/(2) = (2.67-1)/(2)` `= (1.67)/(2) = 0.835`