an aqueous solution boils at 100.512 degree Celsius. The freezing poin

1.	an aqueous solution boils at 100.512 degree Celsius. The freezing point of solution is Kf is 1.86 KKg per mol , Kb is 0.512 KKg per mol
Answer» ANSWER: EXPLANATION: −0.544∘C −0.512∘C −0.272∘C −1.86∘C Answer : C Solution : 0.15=0.512xm,m'=12(0.150.512) ΔTf=1.86×0.150.512×12 Tf=−0.272∘C

an aqueous solution boils at 100.512 degree Celsius. The freezing point of solution is Kf is 1.86 KKg per mol , Kb is 0.512 KKg per mol

Answer»

−0.544∘C

−0.512∘C

−0.272∘C

−1.86∘C

Answer :

Solution :

0.15=0.512xm,m'=12(0.150.512)

ΔTf=1.86×0.150.512×12

Tf=−0.272∘C