1.

An AP consists of 37 terms. The sum of the three middle most terms is 225 and thesum of the last three terms is 429. Find the AP.

Answer»

Total terms =37first term=a, common difference=d

3 middle terms are 18,19,20th termsa+17d+a+18d+a+19d=2253a+54d=225a+18d=75.....(1)

last three terms are 35,36,37th termsa+34d+a+35d+a+36d=4293a+105d=429a+35d=143.....(2)

Subtract equation 1 from 2

17d=68d=4a=75-4(35)a=75-140a=-65

AP is -65,-61,-57....



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