an angle of radius 20cm subtends an angle of 90 degree at the center .

1.	an angle of radius 20cm subtends an angle of 90 degree at the center . find the area of the corresponding major segment of the circle
Answer» Answer: Step-by-step explanation: r=20cm ∠POQ=90° ∴ the triangle is an right angled ISOSCELES Δ first, area of minor segment = area of minor sectorPOQ - area of ΔPOQ = ∅/360 πr² - 1/bh = 90/360 22/72020 = 1100/7 cm² area of MAJOR segment = area of circle - area or minor segment = πr² - 1100/7 cm² = 22/72020 - 1100/7 = 8800/7 - 1100/7 = 7700/7 = 1100cm² hope this is correct , GOOD day:)

an angle of radius 20cm subtends an angle of 90 degree at the center . find the area of the corresponding major segment of the circle

Answer»

Answer:

Step-by-step explanation: r=20cm ∠POQ=90°

∴ the triangle is an right angled ISOSCELES Δ

first, area of minor segment = area of minor sectorPOQ - area of ΔPOQ

= ∅/360 *πr² - 1/*b*h

= 90/360 *22/7*20*20

= 1100/7 cm²

area of MAJOR segment = area of circle - area or minor segment

= πr² - 1100/7 cm²

= 22/7*20*20 - 1100/7

= 8800/7 - 1100/7

= 7700/7 = 1100cm²

hope this is correct , GOOD day:)

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an angle of radius 20cm subtends an angle of 90 degree at the center . find the area of the corresponding major segment of the circle​

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an angle of radius 20cm subtends an angle of 90 degree at the center . find the area of the corresponding major segment of the circle