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An aluminium wire of diameter 4 mm carries a current of 4.4 A. Then the current density is

Answer» EXPLANATION:So here we've an aluminum wire of THICKNESS 4MM Thus, r=2mm and I=2.2ACurrent DENSITY,J=I/AA= πr²= π(2x10^{-3})²J= (2.2/π(2x10^{-3})²) =1.75x10^{5} A/m²


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