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An alternating voltage is represented by `V=80 sin(100 pi t)cos(100 pi t)` volt, What is the peak voltage?A. 20 VB. 30 VC. 40 VD. 50 V |
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Answer» Correct Answer - C `V = 80 sin (100 pi t)cos (100 pi t)` `=80/2 xx 2 sin (100 pi t) cos (100 pi t)` Using `sin 2 theta = 2 sin (theta)/(2) cos (theta)/(2)`, we get `V = 40 sin [200 pi t]` Thus peak voltage `V_(max) or V_(0) = 40 V`. |
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