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An alternating voltage given by V=140sin314t is connected across a pure resistor of `50Omega`. Find the rms current through the resistor. |
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Answer» `I=V/R=140/50sin314t=2.8sin314t=I_0sinomegat` `thereforeI_(rms)=I_0/sqrt2approx2.8/1.4=2A` |
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