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An alternating voltage `E=200sqrt(2)sin(100t)` is connected to a `1` microfarad capacitor through an AC ammeter. The reading of the ammeter shall beA. `10 mA`B. `100 mA`C. `200 mA`D. `20 mA` |
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Answer» Correct Answer - D In a circuit, at an instant `t`, alternating voltage is given by `e = 200 sqrt2 sin 100 t` volts Comparing it, with `e = e_(0) sin omega t` We have, `e_(0) = 200 sqrt2 V, omega = 100 rad s^(-1)` `X_(C) = (1)/(omega C) = (1)/(100 xx (1 xx 10^(-6))) =(200 sqrt2 // sqrt2)/(10^(4))` `= 2 xx 10^(-2) A = 20 mA` |
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