1.

An alternating voltage `E = 200sqrt(2) sin (100 t)V` is applied to a `2 mu F` capacitor through an A.C. ammeter. The reading of the ammeter isA. 4 mAB. 40 mAC. 2 mAD. 3 mA

Answer» Correct Answer - B
`I_(0)=(e_(0))/(X_(C))`
`I_(0)=(e_(0))/((1)/(WC))=wce_(0)`
`I=100xx2xx10^(-6)xx200sqrt(2)`
`I_(rms)=(I_(0))/(sqrt(2))=(100xx2xx10^(-6)xx200sqrt(2))/(sqrt(2))=40mA`.


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