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An alternating current is given by i=62.35sin323t determin I max,f,Irms,Iavg,and form factor​

Answer»

The RESISTANCE of the conductor SHOULD  be 20 ΩExplanation : we know that resistance is the RATIO of voltage to CURRENT(From ohms LAW)Resistance = voltage/current=R=V/IVoltage across the conductor = voltmeter reading = 5.8 vCurrent flowing through the conductor = ammeter reading = 290 mA= 290 x 10⁻³= 0.29 ATHERFORE Resistance,R = 5.8/0.29 = 20 ΩHence the resistance of the conductor will be 20 ΩExplanation:



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