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An alternating current is given by i=(3sin omegat+4cos omegat)A. Find rms current. |
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Answer» Solution :`i=3sin OMEGA t+4 cos omega t` `(int_(0)^(t)i^(2).dt)/(int_(0)^(t)dt)=(int_(0)^(T)(3sin OMEGAT+4cos omegat)^(2)dt)/(T)` `=(1)/(T)int_(0)^(T)(9sin^(2)omegat+16cos^(2)omegat+12sin 2omegat)dt` `=(25)/(2)""therefore i_("rms")=(5)/(sqrt2)A` |
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