1.

An alpha- paticle approaches the target nucleus of copper (Z = 29) is such a way that the vlaue of impact parameter is zero. The distance of closest approach will be

Answer»

`(2pi epsilon_(0)(K.E.)_(alpha))/(29e^(2))`
`(29e^(2))/(2pi epsilon_(0)(K.E.)_(alpha))`
`(4pi epsilon_(0)(K.E.)_(alpha))/(29e^(2))`
`(K.E.)_(alpha)`

ANSWER :B


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